; example with an equation
k1=-4.2
f=x^2+0.2*x+k1
; evaluate at x=3
func 3
; integrate between x=0 to x=3, using 50 steps
integrate 0 3 50
; now more accurately with 5000 steps
integrate 0 3 5000
; Where does the equation = 0
; try between -3 and 0
fzero -3 0 0.001
; check by solving this quadratic equation
quadratic 1 0.2 -4.2